Looking anything real ?

Number Theory Level 2

There are two natural numbers, a a and b b . If L C M ( a , b ) = 19 , H C F ( a , b ) = 1 , LCM(a,b)= 19, HCF (a,b) = 1, then how many real solutions does the following equation have. x 4 + 20 − a b = 0 x^{4} + 20 - ab = 0


The answer is 0.

Manish Mayank by Manish Mayank , 20, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Manish Mayank
Dec 8, 2014

We have, a × b a \times b = L C M ( a , b ) × H C F ( a , b ) LCM(a,b) \times HCF(a,b) So a b ab = 19 Thus the eq. becomes, x 4 x^4 = -1 hence there are no real roots.

0 Helpful 0 Interesting 0 Brilliant 0 Confused

X^4=1 two solution

Shubham Dwivedi - 6 years, 6 months ago

Log in to reply

Sorry I just updated the problem

Manish Mayank - 6 years, 6 months ago

Thanks. Those who previously answered 2 have been marked correct.

In future, if you spot any errors with a problem, you can “report” it by selecting the “dot dot dot” menu in the lower right corner. You will get a more timely response that way.

Calvin Lin Staff - 6 years, 6 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...