Just A Quadratic, Right?

Algebra Level 3

Find the number of solution(s) of x x satisfying log 4 ( x 1 ) = log 2 ( x 3 ) \log_{4}(x - 1) = \log_{2}(x - 3) .

0 1 2 3

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1 solution

log 4 ( x 1 ) = log 4 ( x 3 ) 2 \log_4{(x-1)}=\log_4{(x-3)^2} or x 1 = ( x 3 ) 2 x-1=(x-3)^2 or x 2 7 x + 10 = 0 x^2-7x+10=0 or x = 5 x=5 or x = 2 x=2 .

But x = 5 x=5 is the only solution because if x = 2 x=2 then x 3 x-3 will be negative.

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