Looking for the min-max

max ( a + b + c , b + c + d , c + d + e , d + e + f , e + f + g ) \max(a+b+c, b+c+d, c+d+e, d+e+f, e+f+g)

Let a , b , c , d , e , f , g a,b,c,d,e,f,g be non-negative real numbers such that their sum is 1. What is the minimum value of the expression above?


The answer is 0.333.

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1 solution

To minimize the maximum m m of five expressions, we try to make all of them equal. Thus m = a + b + c = b + c + d = c + d + e = d + e + f = e + f + g . m = a+b+c = b+c+d = c+d+e = d+e+f = e+f+g. From this it follows that a = d = g a = d = g , b = e b =e , and c = f c = f .

We are told that the sum a + + g = 1 a + \cdots + g = 1 ; expression everything in a , b , c a, b, c we get 3 a + 2 b + 2 c = 1 , 3a + 2b + 2c = 1, or 3 m = 1 + b + c . 3m = 1 + b + c. To minimize m m we must therefore minimize b + c b+c , which obviously yields b = c = 0 b = c = 0 . We find m = a = 1 3 0.333 . m = a = \frac 13 \approx \boxed{0.333}.

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