Find the equivalent resistance between points A and B , given that each resistance is 1 Ω and the pattern continues with the same arrangement until the 1 7 6 th vertically oriented resistor, as shown in the image.
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Very good explanation, loved it.
Here is my answer to the challenge: If the bottom-right corner of the five-resistor diamond is R , then the equivalent resistor of that diamond is R ′ = 3 R + 5 5 R + 3 , R ′ − 1 = 3 ( R − 1 ) + 8 2 ( R − 1 ) . By repeating the circuit as shown in this problem, this calculation is repeated over and over. This will cause R to get ever closer to 1.
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Start with the last part of the circuit: the "diamond" of four 1-ohm resistors with a fifth resistor as a bridge.
Because the circuit is symmetric, that bridging resistor is not doing anything: the points it connects have equal potentials, so that there is no current flowing through it.
That simplifies the circuit to the diamond, which is a parallel circuit of two branches of 2 ohms each.
The equivalent resistance of the last part is therefore half of 2 ohm, that is, 1 ohm.
Now this equivalent resistance is the bottom-right corner of the next part of the circuit, which once again is a diamond with a bridge. What we see is that each next part up in the circuit is identical to the previous part; every time the overall resistance is 1 ohm.
After 176 steps, we still have an equivalent resistance of 1 ohm.
Challenge: What if the bottom-right resistor of the last part is not 1 ohm, but R ohms?