Looks like an old problem(it is not)

Classical Mechanics Level 4

We have three particles each of mass m m namely A , B , C A,B,C placed at the vertices of an equilateral triangle of side length l l

At t = 0 t=0 , A A starts moving towards B B , B B starts moving towards C C , C C begins moving towards A A , each with a velocity v v .

Find the distance(not displacement) travelled by A A from t = 0 t=0 till the time when all the three particles collide with each other.

Details and Assumptions

1)The velocity of A is always directed towards B B and is v v ,and similarly for the other two particles.

2) l = 7.5 m e t r e l=7.5 metre

3)Ignore gravity and anything else.


The answer is 5.

Ronak Agarwal by Ronak Agarwal , 23, India

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1 solution

time taken by the particle to reach its centroid (they colllide at the centroid of the triangle) is 2d/3v ..........its speed is v, time taken is 2d/3v ...............distance covered=vt=2d/3=5

1 Helpful 0 Interesting 0 Brilliant 0 Confused

But 7.5 m is length of side of triangle.How then d=7.5m for A?

shivamani patil - 6 years, 6 months ago

@aniket sanghi

Can you post a solution thanks!

Harsh Shrivastava - 4 years, 8 months ago

This is wrong. 2d/3 is the distance from one vertex to the centroid.Where as given these conditions it couldn't have travelled linearly.

Nishchay Suri - 6 years, 5 months ago

1 pending report

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