Lord Of the Rice

A bag contains 100 g m 100 gm of rice. Mayank and Akul w i s h wish to get some rice from it. If they take less than 20 20 percent of what it originally contained, the Lord of the Rice kills both of them instantly. If not, then He changes the amount of rice to h a l f half of what it previously contained. Also the lower limit becomes 20 percent of the new content and the same thing continues. Find the probability that they will safely get the food atleast n n times, where n n is [ min ( s i n x + 2 s i n x ) ] \left[ \min { (sinx+\frac { 2 }{ sinx } ) } \right] for s i n ( x ) > 0 sin(x)>0 .

Details and Assumptions

  1. All the w i s h e s wishes made are random without any prior strategy between the two.

  2. If one doesn't get what he w i s h e s wishes , then also they would have to die. For example if Mayank wishes 80 gm and Akul wishes 40 gm, then one of them won't be ssatisfied and then they would be killed.

  3. For example if they were successful at the first time the bag content would become 50 gm, then 25 gm and so on.

4. [ . ] \left[ . \right] denotes greatest integer function

  1. Each time, Both of us wish for something random between 0 and total content at that time, without any mutual discussion.

We've got more for you at the set Mayank and Akul

0.23 None of these 5.63E-2 0.111 0.512 0.333

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1 solution

Mayank Singh
Sep 11, 2015

First of all see that the value of n must be 3 3 . If you got 2 after applying am gm, see that am gm is not valid here(why, it would be fun to reason it out)

Let's say Mayank took x grams and Akul took y grams.

After their first chance, for their safety 20 < x + y < 100 20<x+y<100 where x and y are real numbers between 0 and 100.

Now how to find the probability that the above statement is valid.

Well the answer lies in the area between lines x+y =20 and x+y =100 bound between the lines x=0,y=0,x=100,y=100

Divide it by the total area (100x100) for the probability.

Next 10 < x + y < 50 10 <x+y<50 Again find the area and divide it by 50x50.

Do that one more time and that's the answer by :-

. 48 . 48 . 48 . 48*.48*.48

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