Lost in the mystery of e i π + 1 \large e^{i \pi } + 1

What is the value to the following expression?

1 + e 180 ° i \huge 1 + e^{- \frac{180 °}{i}}


Hint: Use the hint in the topic

1 -1 π \pi 0 -2

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Munem Shahriar
Nov 26, 2017

1 + e 18 0 i 1+ e^{\large -\frac{180^\circ}{i}}

= 1 + e π i = 1+ e^{\large -\frac{\pi}{i}}

= 1 + e π ( i ) i ( i ) = 1 + e^{\large -\frac{\pi(-i)}{i(-i)}} ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ; [ Multiply by i i ] ;\left[\text{Multiply by} \dfrac{-i}{-i}\right]

= 1 + e ( π i ) = 1 + e^{\large -(-\pi i)}

= 1 + e π i = 1 + e^{\large \pi i}

= 1 1 = 1- 1

= 0 = \boxed{0}

Syed Hamza Khalid
Nov 25, 2017

1 + e 180 ° i \large 1 + e^{- \frac{180 °}{i}} = e i π + 1 \large e^{i \pi } + 1

= 0 \therefore \implies = 0

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...