A calculus problem by ابراهيم فقرا

Calculus Level 3

Let a , b , c a,b,c be complex numbers. Find the minimum value of F ( a , b , c ) = π π x a b cos x c sin x 2 d x . F(a,b,c) = \int_{-\pi}^\pi | x - a- b \cos x - c \sin x|^2 \, dx.


Note: Gram-Schmidt might be relevant here.


The answer is 8.104.

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1 solution

Otto Bretscher
Dec 7, 2018

All the functions x , 1 , cos x , sin x x,1,\cos x, \sin x are orthogonal, meaning that π π f ( x ) g ( x ) d x = 0 \int_{-\pi}^{\pi} f(x)g(x)dx=0 , except for x x and sin x \sin x . For a real c c , we find that π π ( x c sin x ) 2 d x = 2 π 3 3 + c ( c 4 ) π \int_{-\pi}^{\pi} (x-c\sin x)^2\ dx=\frac{2\pi^3}{3}+c(c-4)\pi is minimal when c = 2 c=2 , and the minimal value is 2 3 π 3 4 π 8.1045 \frac{2}{3}\pi^3-4\pi \approx \boxed{8.1045} when we let a = b = c = 0 a=b=\Im c=0 .

Well done .

ابراهيم فقرا - 2 years, 6 months ago

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