Lower Bound for Zeta function on set of natural numbers

What is the greatest lower bound for the zeta function ζ ( n ) \zeta(n) , where n N n\in \mathbb{N} ?


The answer is 1.

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1 solution

Patrick Corn
Oct 10, 2019

By thinking about areas of rectangles under a curve, we get ζ ( n ) = 1 + k = 2 k n 1 + 1 x n d x = 1 + 1 n 1 . \begin{aligned} \zeta(n) = 1 + \sum_{k=2}^\infty k^{-n} &\le 1 + \int\limits_1^{\infty} x^{-n} \, dx \\ &= 1+\frac1{n-1}. \end{aligned} So we have 1 < ζ ( n ) 1 + 1 n 1 , 1 < \zeta(n) \le 1 + \frac1{n-1}, so by the squeeze theorem , lim n ζ ( n ) = 1. \lim\limits_{n\to\infty} \zeta(n) = 1. So the greatest lower bound is 1 . \fbox{1}.

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