Lucky man problem

Probability Level 3

There are 2500 people , arranged in a circle and given a number according to their position as first person is numbered as 1 and so on up till 2500th person Now first person has gun he shoots 2nd person and pass the gun to 3rd person and 3rd one will shoot 4th person and pass gun to 5th person and so on .This game is ended at one person is alive at the end ,SO QUESTION IS THAT WHAT WOULD BE THE NUMBER OF PERSON WHO IS ALIVE AT THE END ??


The answer is 905.

Dwarkesh Virkhare by Dwarkesh Virkhare , 20, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Dwarkesh Virkhare
May 26, 2018

2(2500- 2028)+ 1 let N be the total no of people and 2028 is nearest two power number and where N=2500 and 2028 is 11th power of two so we get by solving above relation is 905 , *905th person will be alive *

0 Helpful 0 Interesting 0 Brilliant 0 Confused

2048 is 2^11,not 2028

X X - 3 years ago

Could you explain this better?

Keertana Pillai - 3 years ago

ACTULLY WE HAVE TO FIND THE NEAREST POWER OF 2 TO 2500

Dwarkesh Virkhare - 2 years, 10 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...