Two natural numbers m and n have natural divisors
a 1 , a 2 , . . . . . . . . . . . . . . . . , a p
and
b 1 , b 2 , . . . . . . . . . . . . . . . . . . . . . . . . b q
and it is known that
a 1 + a 2 + . . . . . . . . . . . . . . . . . . . . . . . . . . . . . + a p = b 1 + b 2 + . . . . . . . . . . . . . . . . . . . . . . . . . + b q
a 1 1 + . . . . . . . . . . . . . . . . . . . . a p 1 = b 1 1 + . . . . . . . . . . . . . . . . . . . . . . . . . . . . . + b q 1
Find the value of n m
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As sum of divisors and sum of reciprocals of divisors is same, it is possible only if all divisors of m and n are same. i.e. both m and n are same so m/n = 1