ma + th = math?

How many ordered quadruples of positive integer solutions are there to the equation M A + T H = M A T H ? MA + TH = MATH \, ?

Clarification:

  • The above is 1 equation in 4 variables: ( M × A ) + ( T × H ) = M × A × T × H . (M\times A)+(T\times H)=M\times A\times T\times H.
0 1 2 3 4 5 6 7

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1 solution

The given equation can be rewritten as m a t h m a t h = 0 ( m a 1 ) ( t h 1 ) = 1 math - ma - th = 0 \Longrightarrow (ma - 1)(th - 1) = 1 .

As m , a , t , h m,a,t,h are all positive we know that m a , t h 1 ma, th \ge 1 , so we must have

m a 1 = t h 1 = 1 m a = t h = 2 ma - 1 = th - 1 = 1 \Longrightarrow ma = th = 2 .

So there are two options for each of ( m , a ) (m,a) and ( t , h ) (t,h) , namely ( 1 , 2 ) (1,2) and ( 2 , 1 ) (2,1) , so for ( m , a , t , h ) (m,a,t,h) there are a total of 2 × 2 = 4 2 \times 2 = \boxed{4} options.

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