How many ordered quadruples of positive integer solutions are there to the equation
Clarification:
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The given equation can be rewritten as m a t h − m a − t h = 0 ⟹ ( m a − 1 ) ( t h − 1 ) = 1 .
As m , a , t , h are all positive we know that m a , t h ≥ 1 , so we must have
m a − 1 = t h − 1 = 1 ⟹ m a = t h = 2 .
So there are two options for each of ( m , a ) and ( t , h ) , namely ( 1 , 2 ) and ( 2 , 1 ) , so for ( m , a , t , h ) there are a total of 2 × 2 = 4 options.