Machenics problem by Aman

Classical Mechanics Level 1

Distance covered by an accelerating particle of mass 50kg at any time t is given by the function:- $d=20t+10t^{2}$ Where d is the distance covered by particle(in meter) in t seconds Calculate the force that particle is experiencing( in newtons)

The answer is 1000.

1 solution

A Former Brilliant Member
Aug 29, 2014

$\quad \quad \quad \quad \quad \quad \quad s\quad =\quad 20t\quad +\quad 10{ t }^{ 2 }\\ Differentiating\quad both\quad sides\quad w.r.t\quad time,\\ \frac { d }{ dt } s\quad =\quad \frac { d }{ dt } (20t+10{ t }^{ 2 })\quad =\quad 20+20t\\ Differentiating\quad again\quad w.r.t\quad time\\ \frac { { d }^{ 2 } }{ { dt }^{ 2 } } s\quad =\quad \frac { d }{ dt } (20+20t)\quad =\quad 20m{ s }^{ -2 }\\ Now,\quad Force\quad =\quad mass\quad \times \quad acceleration\\ \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad =\quad 50kg\quad \times \quad 20m{ s }^{ -2 }\\ \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad =\quad 1000\quad N$

Cheers!!:)

Machenics problem by Aman

The answer is 1000.

1 solution

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