Machine Design
Classical Mechanics
Level
2
A 1" diameter shaft is to be replaced with a hollow shaft of the same material, weighing half as much, but equally strong in torsion. The outside diameter of the hollow shaft is to be 1.5" , Find the inside diameter
The answer is 1.32.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
1 solution
Mass of hollow =(1/2) mass of solid m=wV wV 1 =(1/2)wV 2 Thus, v 1 =(1/2)v 2 (pi/4)(D outer^2 - D inner^2)(L)=(1/2)(pi/4)(d^2)(L) 1.5^2-d(inner)^2=(1/2)(1)^2 D_inner=1.323