Magic of Math#10

Geometry Level 2


The answer is 3.5.

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1 solution

Kay Xspre
Sep 9, 2015

c o t ( π 2 ζ ) = t a n ( ζ ) cot(\frac{\pi}{2}-\zeta) = tan(\zeta) , hence the question may be written as ( 1 + s e c 2 ( ζ ) t a n 2 ( ζ ) c o s e c ( θ ) ) ( 1 t a n ( θ ) s e c ( θ ) ) \sqrt{(1+\frac{sec^{2}(\zeta)-tan^{2}(\zeta)}{cosec(\theta)})(1-\frac{tan(\theta)}{sec(\theta)})} or in a more simplified form as ( 1 + s i n ( θ ) ) ( 1 s i n ( θ ) ) \sqrt{(1+sin(\theta))(1-sin(\theta))} which may be put further to 1 s i n 2 ( θ ) \sqrt{1-sin^{2}(\theta)} , an equivalent to c o s ( θ ) |cos(\theta)| . Given that 0 < θ < π 2 0 < \theta < \frac{\pi}{2} , the value may be released from the absolute value as c o s ( θ ) = 2 7 cos(\theta) = \frac{2}{7} , hence s e c ( θ ) = 7 2 sec(\theta) = \frac{7}{2}

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