Shown right is a "magic square" in which the sums of each diagonal, each row, and each column are all equal.
Find y + z .
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I did the same...
Excellent Paola
Check for (x, y ,z, ,w,v) to be (22, 6 ,0, 19 3) satisfies the conditons So ans. can be any no as 6 +2x x is whole no.
v + 2 4 + w = v + 1 8 + 2 5 ⟹ w = 4 3 − 2 4 = 1 9
z + 2 5 + 2 1 = 2 4 + x + z ⟹ x = 4 6 − 2 4 = 2 2
w + y + 2 1 = w + x + 2 5 ⟹ y = 2 2 + 2 5 − 2 1 = 2 6
2 5 + z + 2 1 = w + y + 2 1 ⟹ 4 6 + z = 1 9 + 2 6 + 2 1 ⟹ z = 6 6 − 4 6 = 2 0
Finally,
y + z = 2 6 + 2 0 = 4 6
The square is
23 | 24 | 19 |
18 | 22 | 26 |
25 | 20 | 21 |
Sum is 66. y + z = 2 0 + 2 6 = 4 6
W+Y+21=V+18+25, V+X+21=W+X+25 V-W=4 ,put this in 1st equation we get Y=26 18+X+Y=25+Z+21 W+Y+21=W+X+25 Put Y=26 in above ,we get X=22 Then put X=22,Y=26 in 3rd equation we get Z=20 Hence Y+Z=46
18 + 25 + v = magic number
18 + 25 = 43
43 + v = magic number
24 + w + v = magic number
24 + w + v the row has v:
24 + w = 43
w = 19
same method with diagonal:
21 + x + v = magic number
21 + x = 43
18 + 25 + v = magic number
43 + v = magic number
21 + x + v has v
Anyway...
21 + x = 43
x = 22
Now we have the other diagonal complete
25 + 22 + 19
25 + 22 + 19 = magic number
25 + 22 + 19 = 66
66 = magic number
Now calculate z and y
22 + 24 + z = 66
z = 20
19 + 21 + y = 66
y = 26
20 + 26 = z + y = 46, the correct answer.
Did anyone try it using systems of equations?
I simplified the process and noticed this:
24+ w+ v (eliminated)
1 + 18 = 19 for w
21 + v + x (eliminated)
4 + 19 = 23 for v
18 + x+ y (eliminated)
3 +19 = 22 for x
Thanks.
21 24 19 18 22 24 25 18 21
Also works, so y + z could also equal 42... v=25 x=22 w=19 y=24 z=18 also works so 42 is also a valid solution
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2 4 + x + z = 2 5 + z + 2 1
2 4 + x = 2 5 + 2 1
x = 2 2
2 5 + 2 2 + w = 2 1 + y + w
2 5 + 2 2 = 2 1 + y
y = 2 6
Sum of each row is 1 8 + 2 2 + 2 6 = 6 6
2 5 + 2 1 + z = 6 6
z = 2 0
∴ y + z = 2 6 + 2 0 = 4 6