Magical Square Numbers

Since all three numbers are perfect squares that means that each digit of the numbers is the last digit of a perfect square. these digits are 1, 4, 5, 6, 9 and 0. The only perfect square that can be formed is 196 so take that as ACB and the other numbers will be 961 and 169. So if you subtract them you will get 596.

Hello,since perfect squares for 3 digit numbers,

Stated ABC < ACB < CBA,

we know that for 3 digit number perfect squares, the range is [100,961] is equivalent to [10^2,31^2],

so for the 3 digit numbers, i took the max in the range that is 961,

so for the 3 digit number 961,this should be CBA cause it is the highest 3 digit number for perfect squares,

CBA = 961, C=9,B=6,A=1,

check for ABC and ACB,are they perfect squares,

ABC = 169(yes,it is a perfect square of 13)

ACB= 196(yes,it is a perfect square of 14)

Therefore, ABC < ACB < CBA = 169 < 196 < 961

CBA - ACB - ABC = 961 - 196 - 169 = 596...

Thanks...

Same as Skaid Dkhu said and try square root these numbers 169,196,961.it may help.