A current of strength flows around the path on the left and yields a field of strength pointing to the right,
What field is produced when the current flows around the path shown on the right?
Details and Assumptions:
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You can always write two cancelling currents in edges where there's no current a priori . Doing this to the three front edges not crossed by currents, you "fill up" complete circuits at the front, left and down faces. By superposition's principle, follows B = B 0 ( x ^ + y ^ + z ^ ) .