Magnetic Moment of a loop

Electricity and Magnetism Level 2

A loop carrying current $I$ lies in the $x - y$ plane as shown in the figure. The unit vector $\hat{k}$ is coming out of the plane of the paper. The magnetic moment of the current loop is

\left( 2 \pi + 1 \right) a^2 I \hat{k}

$\left( \frac{\pi}{2}+1 \right) a^2 I \hat{k}$

a^2 I \hat{k}

\left( \frac{\pi}{2}+1 \right) a^2 I \hat{k}

1 solution

Steven Zheng
Jul 16, 2014

We need the area enclosed in the loop, which is $(\frac{\pi}{2}+1)a^2.$ Multiply this by the current I. Using the right-hang rule, we have the cross product pointing out of the page. Hence, the answer is
$(\frac { \pi }{ 2 } +1)(a^{ 2 })I\hat { k } .$

this came in iit 2012

Aryan Jakhar - 6 years, 10 months ago

Magnetic Moment of a loop

1 solution

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