Magnetism Series #5

A single-layer conducting coil is wound with no gap between adjacent turns on a cylindrical frame of radius R R .Diameter of cross-section of the wire used is d ( d < < R ) d(d<<R) .
If breaking stress of the material of the wire is λ b \lambda_{b} , at what magnitude of current will the coil rupture?
Answer comes in the form of I = λ π d β γ μ 0 R α I=\sqrt{\frac{\lambda πd^{\beta}}{\gamma \mu_{0}R^{\alpha}}}
Type your answer as α + β + γ = ? \alpha+\beta+\gamma=?

The problem is taken from my Physics Book.

Thanks in advance if you are going to post solution


The answer is 6.

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