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Chemistry Level 1

When the reaction

2NO 2 ( g ) N 2 O 4 ( g ) , Δ H = 58 kJ \text{2NO}_2(g) \rightleftharpoons \text{N}_2\text{O}_4(g),\qquad\Delta H=-58 \text{ kJ}

is in chemical equilibrium, which of the following can increase the yield of N X 2 O X 4 ? \ce{N2O4}?

Increasing pressure and adding N O X 2 \ce{NO2} Increasing the temperature Waiting until the equilibrium shifts spontaneously Adding N X 2 O X 4 \ce{N2O4}

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1 solution

Tong Choo
Feb 19, 2014

There are two answers to this question, B and D. Increasing temperature will in fact increase both the rate of the forward and backward reactions, while increasing the concentration or pressure of NO2 will also increase the rate of the forward reaction. The setter of this question has confused the difference between forward reaction rate and position of equilibrium.

Change of heat is negative means a cooler environment shall enhance forward process as they release heat easily to cool environment. Yield means gain of which added in N 2 O 4 N_2 O_4 enhance backward process while added amount is not counted as yield. Notice that 2 volume of N O 2 NO_2 is changed into 1 volume of N 2 O 4 N_2 O_4 . Increase pressure is therefore enhance forward reaction. Only the B you meant can be correct!

Lu Chee Ket - 5 years, 4 months ago

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