MAKE IT A PERFECT SQUARE

Algebra Level pending

The sum of possible integral values of a such that quadratic polynomial [x + a] [x +2013] + 1 is a perfect square is

1 solution

Rohit Kumar
Jan 7, 2015

let -

$(x + a)(x + 2013) = k^{2} - 1$

then

$(x + a)(x + 2013) = (k + 1)(k - 1)$

so, the difference between $(x + a)$ and $(x + 2013)$ should be $2$ .

so, $a = 2011, 2015$ .

answer = $4026$

good boy!!!!!!!

divyansh tripathi - 6 years, 5 months ago