Make sure it maintains the divisibility

What is the smallest positive integer x x such that x , x 1 x,x-1 and x 2 x-2 are each divisible by distinct perfect squares?

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The answer is 9.

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1 solution

9 is divisible by 9, a perfect square. 8 is divisible by 4. 7 is divisible by 1. Therefore x is 9.

thought fr 9 ...at frst ..but didn't remind of 1 in the case of 7....

tanmay goyal - 6 years, 4 months ago

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