2 2 2 2 = 1
Is it possible to make this equation true by inserting the appropriate operations? Any operations and functions can be used.
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What about BODMAS rule? :)
2 ÷2 x 2 ÷ 2 = 1
(2+2-2-2)! =1
(2 x 2) ÷ (2 x 2)=1
...
There are many ways to do .
2 × 2 2 × 2 = 2 + 2 2 + 2 = 2 2 2 2 = 2 × 2 2 2 = 1
2 2 2 2 = ( 2 2 ) 2 2 = ( 2 2 ) 2 × 2 = ( 2 2 ) 2 + 2 = 1
( 2 2 ! ) 2 − 2 = 2 ( 2 − 2 ) 2 = 1
cos^2(2) + sin^2(2) + 2 - 2 = 1
2 / 2 +2 - 2 OR 2 / 2 - 2 + 2
(2/2)/(2/2).....It supports BODMAS rule....
Any operations and functions can be used.
22/22=1
QED
2^2 / 2^2 = (2^2) / (2^2) = 4 / 4 = 1
2/2 + 2/2 = 1
According to BODMAS rule..
2/2 =1 1+2+2=5 You mean (2+2)/(2+2)
2 ÷ 2 ÷ 2 ÷ 2 = 1 2 ÷ 2 × 2 ÷ 2 = 1 2 − 2 + 2 ÷ 2 = 1 ( 2 × 2 ) ÷ ( 2 × 2 ) = 1 There are infinite possible ways..
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2 ÷ 2 ÷ 2 ÷ 2 = 4 1 .
But one example is enough to show that its possible to make the equation true. :)
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2 - 2 +2÷2 = 1