Hydrogen gas is ignited with oxygen gas to produce water. If N oxygen gas in ml of solution is added to N hydrogen gas in ml of solution, then find the weight of water formed in grams.
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For hydrogen:-
Let moles included be x
Then 6 6 . 6 7 = 7 5 x × 1 0 0 0 x = 5
For oxygen:-
Let moles included be y .
Then 4 0 = 5 0 y × 1 0 0 0 y = 2
2 H X 2 + O X 2 2 H X 2 O
Lets see the ratio of the moles to the stoichiometry coefficients of the reactant.
For hydrogen it is 2 5 = 2 . 5
For oxygen it is 1 2 = 2
Since oxygen has lower ratio, it is limiting.
Now, 1 mole of oxygen produces 2 moles of water.
So, 2 moles of oxygen produces 4 moles of water which is equal to 4 × 1 8 = 7 2 g