Man and particle

Classical Mechanics Level pending

A particle of mass m m moves with a uniform speed V 2 V_2 in a circle of radius R R , centered at ( R , 0 ) (R,0) in the x − y x-y plane. A person moves along the y y -axis with a uniform velocity V 1 V_1 . At t = 0 t= 0 , the man as well as the particle are located on the x x -axis and moving in the same direction. Find the angular momentum of this particle with respect to the man at the time t = π R 2 V 2 t = \dfrac{\pi R}{2V_2} .

[ m V 1 R ( 1 + π 2 ) − m V 2 R ] ( − k ^ ) \left [ mV_1 R \left(1 + \frac\pi2 \right) - mV_2 R \right ] (-\widehat k) m V 2 R ( − k ^ ) mV_2 R (-\widehat k ) [ m R ( π V 1 2 ) 2 + V 2 2 ] ( k ^ ) \left [ mR \sqrt{ \left( \frac {\pi V_1} 2 \right)^2 + V_2 ^2 } \right ] (\widehat k) m R ( π V 1 2 + V 2 ) ( + k ^ ) mR \left( \frac{\pi V_1}2 + V_2 \right) (+\widehat k)

Ayush Choubey by Ayush Choubey , 22, India

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