Since price of mangoes decreases by 25%, I can purchase 4 mangoes more for 60$. Find the original price of 1 mango.
please explain the solution in comments thank you
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Original price of one mango= x Let's assume that the man originally bought y mangoes. Then:
xy = 60
0.75(x)(y + 4) = 60 => 0.75(60) + 3x = 60
x = (60 - 45)/3 = 5 rs.
P * Q = E
P= PRICE OF 1 QUANTITY
Q=NO. OF QUANTITY
E= EXPENDITURE OR TOTAL PRICE
let us assume that my total expenditure is 60$ i.e
p * q = 60 ............a
now when the price decreases by 25% quantity increases by 4 for 60$ which means 0.75p * (q+4)=60
=>0.75pq + 3p = 60
but pq=60 from a
so
=>0.75 * 60 +3p=60 =>p=5 hence original price of 1 mango is 5$.
The equation should be 6 0 = P Q = ( 0 . 7 5 P ) ( Q + 4 ) .
This gives us 3 1 Q = 4 , so Q = 1 2 and P = 1 2 6 0 = 5 .
You can verify that when price decreases by 25% to 5 × 4 3 = 3 . 7 5 , then you can buy 3 . 7 5 6 0 = 1 6 mangoes, which gives us 4 more.
Edit: Calculation error initially.
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sir what's wrong in this solution P * Q = E
P= PRICE OF 1 QUANTITY
Q=NO. OF QUANTITY
E= EXPENDITURE OR TOTAL PRICE
let us assume that my total expenditure is 60$ i.e p * q = 60 ............a
now when the price decreases by 25% quantity increases by 4 for 60$ which means 0.75p * (q+4)=60
=>0.75pq + 3p = 60
but pq=60 from a
so =>0.75 * 60 +3p=60
=>p=5
hence original price of 1 mango is 5$.
Cost = Price × Quantity
1 = (3/4) × (4/3)
100% = (100% – 25%) × (100% + 33⅓%)
4 is the extra mangoes we get to buy from the drop of price, so it's the increase of 33⅓% from the original quantity.
Original quantity
= 4 ÷ 33⅓%
= 12
Original price
= 60 ÷ 12
= $5.00
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