Many digits

S ( n ) = k = 1 n k ! S(n) = \sum_{k=1}^n k!

With S ( n ) S(n) defined as above, how many digits are there in S ( 47000 ) S(47000) ?


The answer is 199180.

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1 solution

Giorgos K.
Feb 20, 2018

Mathematica
IntegerLength@Sum[k!, {k, 47000}]

The answer is 199180

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