Many Facts!

1!+2!+3!+4!+5! =1+2+6+24+120 =153

First step is to calculate the value of Each Factor, To Sum After them , Thus we have :

$1!$ $=$ $1$

$2!$ $=$ $2 \times 1$ $=$ $2$

$3!$ $=$ $3 \times 2 \times 1$ $=$ $6$

$4!$ $=$ $4 \times 3 \times 2 \times 1$ $=$ $24$

$5!$ $=$ $5 \times 4 \times 3 \times 2 \times 1$ $=$ $120$

For All We sum End Results and found the solution :

$1!$ $+$ $2!$ $+$ $3!$ $+$ $4!$ $+$ $5!$ $\Rightarrow$ $1$ $+$ $2$ $+$ $6$ $+$ $24$ $+$ $120$ $=$ $\boxed{153}$

Anyone notice this is a narcissistic number? 1^3+5^3+3^3=153

$(1) + (2 * 1) + (3 * 2 * 1) + (4 * 3 * 2 * 1) + (5 * 4 * 3 * 2 * 1) \\1 + 2 + 6 + 24 + 120 = 153$

1+2+6+24+120=153

$1! + 2! + 3! + 4! + 5!$

Just putting the value of the factorials

$\implies 1 + 2 + 6 + 24 + 120$

$\implies 153$

Find the factorials of each number and add them together: 1- 1 (no other numbers) 2- 2x1=2 3- 3x2x1=6 4- 4x3x2x1=24 5- 5x4x3x2x1=120

1+2+6+24+120=153

Read the Details and assumptions for the solution on getting the factorials.

1! = 1 2! = 2X1 = 2 3! = 3X2X1 = 6 4! = 4x3x2x1 = 24 5! = 5x4x3x2x1 = 120

1+2+6+24+120 = 153