Many lengths, only one radius

Geometry Level 3

A given circumference Γ \Gamma is inscribed in regular polygon of 74 74 sides. If Γ \Gamma has an area of 1369 π 1369\pi and the polygon has an area of 2.3 7 3 . 3 2 2.37^{3}.3^{2} . What is the side length of the polygon which has Γ \Gamma inscribed?


The answer is 666.

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1 solution

Mikael Marcondes
Jan 8, 2015

The area of a regular polygon can be written as n . l . r 2 \frac{n.l.r}{2} , where n n is the number of sides, l l is the length of each side and r r is the length of the radius of the inscribed circumference Γ \Gamma . As we know, if the area of Γ \Gamma is 1369 π 1369\pi , its radius is equal to 37 37 . From the equation, we get:

A = 2.3 7 3 . 3 2 = 74. l . 37 2 l = 666 A=2.37^{3}.3^{2}=\frac{74.l.37}{2}\rightarrow \boxed {l=666}

Question seems to be wrong! It has asked for radius of T, not the side length of the polygon.

Prabir Chaudhuri - 6 years, 5 months ago

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Yes, I just realized I've typed it wrong today. There's no way to edit it, except when other people report this problem, because I can't report ir by myself.

Mikael Marcondes - 6 years, 5 months ago

I've fixed it. Thanks for the hint.

Mikael Marcondes - 6 years, 5 months ago

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