Marble Trouble

A bag contains 6 green, 5 gray, and 4 violet marbles.

If a marble is drawn at random from the bag, what is the probability that the marble drawn is not green? (in %)


The answer is 60.

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5 solutions

probability that the marble drawn is not green = (gray+violet)/(green+violet+gray) = 60%

I did same as above problem.

TEHREEM SADAQAT - 6 years, 10 months ago
Suresha Hd
Jul 8, 2014

Probability=(4+5)/15 . The probability will be 9/15 i.e. 60% in percentage.

Fox To-ong
Feb 12, 2015

thats 1 - ( 6 /15) = .60

Zi yang Lim
Nov 30, 2014

Gray+Violet=9 Marbles.Hence you add 6 marbles(green) which becomes 15.100 divided by 15 is 6.666....,and when multiplied by 9 and rounded to the nearest whole number,it sums up to 60

Bryan Dayupay
Sep 3, 2014

probability of a marble drawn is not green so it can be gray or violet; so (gray+violet)/ (green+gray+violet)= 9/15 = .06 x 100 = 60%

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