Marbles & Bags

The solution is just the number of ways you can choose 4 bags multiplied by the order that the marbles could be in...

${ _{ 6 }C_{ 4 }\times 4!=\frac { 6! }{ 2!4! } \times 4!=\frac { 6! }{ 2! } =\frac { 720 }{ 2 } =360 }$

where ${ _{ 6 }C_{ 4 }}$ is the number of ways you can choose 4 bags from 6

and $4!$ is the number of ways you could arrange the marbles in those 4 bags