Martha's Expression and Hypothesis

Level 1

Martha investigates the expression 9 n 8 n 9^n-8^n . She substitutes 1, 2, 4, 6, and 12 for n n and here are her results:

  • 9 1 8 1 = 1 9^1-8^1=1 , which shares no common factors with 18 other than 1.
  • 9 2 8 2 = 17 9^2-8^2=17 , which again shares no common factors with 18 other than 1.
  • 9 4 8 4 = 2465 9^4-8^4=2465 , which yet again shares no common factors with 18 other than 1.
  • 9 6 8 6 = 269297 9^6-8^6=269297 , which still shares no common factors with 18 other than 1.
  • 9 12 8 12 = 213710059745 9^{12}-8^{12}=213710059745 , which unsurprisingly still shares no common factors with 18 other than 1.

She makes a hypothesis that the expression she was investigating will never share any common factors with 18 other than 1 for any positive number n n .

Is her hypothesis right?

No, it depends on the value of n n Yes, her hypothesis is true for any positive integer n n

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1 solution

X X
Sep 8, 2018

9 n + 1 8 n + 1 = 9 n + 9 n 1 8 1 + 9 n 2 8 2 + . . . + 9 2 8 n 2 + 9 1 8 n 1 + 8 n 9^{n+1}-8^{n+1}=9^n+9^{n-1}8^1+9{n-2}8^2+...+9^28{n-2}+9^18^{n-1}+8^n

= ( 9 n + 9 n 1 8 1 + 9 n 2 8 2 + . . . + 9 2 8 n 2 + 9 1 8 n 1 ) + 8 n =(9^n+9^{n-1}8^1+9{n-2}8^2+...+9^28{n-2}+9^18^{n-1})+8^n (which is obviously not a multiple of 3.)

= 9 n + ( 9 n 1 8 1 + 9 n 2 8 2 + . . . + 9 2 8 n 2 + 9 1 8 n 1 + 8 n ) =9^n+(9^{n-1}8^1+9{n-2}8^2+...+9^28{n-2}+9^18^{n-1}+8^n) (which is obviously not a multiple of 2.)

Hence, every positive n n will make the expression and 18 coprime.

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