Mashrur's palindromes

The first 4 digit palindrome is 1001 with the next being 1111. We find that we only get a three digit number when we subtract 32 from 1001.Therefore this is the only number.

Since the numbers differ by 32 and one is a 3 digit number and the other is a 4 digit number, the 4 digit number starts and ends with 1, and the 3 digit number starts and ends with 9. The numbers being abba and xyx Their values being 1000a+100b+10b+a and 100x+10y+x and the values of a and x being 1 and 9 respectively. The equation now becomes 1001+110b= 909+10y+32 simplifying the equation we get 1001-941=10y-110b or 60=10y-110b Now for all non zero values of b the equation takes negative values. The only non negative values which satisfy the equation are b=0 and y=6 Thus 1001 and 969

x can at most be 999, so x+32 is at most 1031. Another constraint is that the minimum value x+32 can have is 1000. But the only palindrome between 1000 and 1031 is 1001, which means that x+32 is 1001. Hence, x=969.

969(three-digit palidrome) + 32 = 1001(four digit palidrome)

LOL i just guess

Since only $32$ is being added to $x$ to produce a 4-digit number, we notice that $x$ must have hundreds digit $9$ , and, since $x$ is a palindrome, its units digit must be $9$ as well. Also, we notice that $x + 32$ must have thousands digit of $1$ , and therefore, units digit of $1$ . And, since $x$ must have hundreds digit of $0$ , $x + 32 = 1001$ , and $x = \boxed{969}$ .

You have a four-digit palindromes, so you would do 1001-32= 969 969 would be your answer

A three digit palindrome that turns larger than 1000 when adding 32 can only be: 969, 979, 989 and 999. Test adding 32 to those four!

as we must find the palindrome that is 900 or up and if we add up 32 at least we obtain a palindrome that is 4 digit , the closest is 1001 thus we know the 4 digit palindrome , or x+32 is 1001 so we can subtract 32 from 1001 to obtain the x here is the following details 1001-32 = 969 and it's fulfilled because 969 is palindrome indeed

Since x is a three digit number and by adding 32 to x, a four digit number is obtained, thus x must be greater than 968. The nest Palindrome number after 968 is 969. 969+32=1001 which is also a palindrome thus x = 969