Mass and Wedge

Classical Mechanics Level 2

A block of mass m m is pushed towards a movable wedge of mass n m nm and height h h . You may assume all the surfaces to be smooth. The minimum value of the velocity u u with which the block m m must be projected so that it would reach the top of the wedge is

2 g h ( 1 − 1 n ) \sqrt { 2gh\quad (1-\frac { 1 }{ n } ) } 2 g h \sqrt { 2gh } 2 g h ( 1 + 1 n ) \sqrt { 2gh\quad (1+\frac { 1 }{ n } ) } n 2 g h n\sqrt { 2gh }

Rishav Koirala by Rishav Koirala , 22, Singapore

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1 solution

Rishav Koirala
Apr 22, 2014

  • The wedge is movable so use momentum conservation to find the combined velocity of wedge + mass system.

  • Then use energy conservation for the system.

17 Helpful 0 Interesting 0 Brilliant 0 Confused

It is the only way.

Arghyanil Dey - 7 years, 1 month ago

Thank you :D

Jung Hyun Ran - 7 years ago

Can we do using dynamics

Babu Ullooo - 3 years, 9 months ago

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