Mass Atomic - Chemistry

Chemistry Level pending

A metal X \ce{X} is reacted with hydrochloric acid according to the balanced equation:

X ( s ) + 3 H C l ( a q ) → X 3 + ( a q ) + 3 C l X − ( a q ) + 3 2 H X 2 ( g ) \ce{X}(s)+\ce{3HCl}(aq)\rightarrow\ce{X}^{3+}(aq)+\ce{3Cl-}(aq)+\frac{3}{2}\ce{H2}(g)

If 500 mL of a 3 M solution of hydrochloric acid react completely with 26.0 g of this metal, what is the atomic mass of X \ce{X} ?


The answer is 52.

Gabriel Merces by Gabriel Merces , 23, Brazil

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1 solution

Joem Camacho
Mar 7, 2014

First, find the moles of Hydrochloric acid used. m o l e s H C l = 3 m o l H C l 1000 m l ( 500 m l ) = 1.5 m o l H C l moles\quad HCl\quad =\quad \frac { 3\quad mol\quad HCl }{ 1000ml } \left( 500ml \right) \quad =1.5\quad mol\quad HCl .

Since 26.0 g of metal was used with 1.5 mol HCl, and 3 moles HCl were reacted to 1 mol of metal , the atomic mass would be

26.0 g M 1.5 m o l H C l ( 3 m o l H C l 1.0 m o l M ) = 52.0 g m o l − 1 \frac { 26.0g\quad M }{ 1.5mol\quad HCl } \left( \frac { 3\quad mol\quad HCl }{ 1.0\quad mol\quad M } \right) =52.0\quad g\quad { mol }^{ -1 } of metal

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