Mass of a ball

Applying Newton's Second Law of Motion we know that $F = ma$

Rearranging we determine $m = \frac{F}{a}$

We also know that the net force applied to the ball is $40N$ and that it accelerates at $100ms^{-2}$

Inputting the provided values into the obtained formula we determine the mass of the ball

$m = \frac{40N}{100ms^{-2}} = 0.4kg$

Let the net force of the ball is $40 N$ = $40 kg.m/s^2$

And the ball accelerates at $100 m/s^2$ ,

Then the mass of the ball is $40/100$ = $0.4 kg$

According to Newton's $2^{nd}$ \ Law of Motion,

Sum of all forces acting on the body = Product of mass * it's acceleration

Implies,

40 = $M \times a$

40 = $M \times 100$

$\frac{40}{100}$ = M

M = 0.4 Kg

By Newton's 2nd law, We know that, $F=ma$ ...

Here, $F=40N$ and $a=100m/s^2$ ...

So, $F=ma \Longrightarrow 40N=m \times 100m/s^2$

$\Longrightarrow m=\frac {40kg m/s^2}{100m/s^2} \Longrightarrow m=0.4 kg$

Therefore, the mass of the ball and the required answer is $\fbox {0.4}$

F=ma 40=m*100 m=40/100 m=0.4kg

f = 40N, a = 100m/s^2 e m = ?

Aplicando a equação f = m * a (física, meu amor), temos:

  40 = m * 100
   m = 0.4kg.

F = ma

40 = m x 100

m = 0.4 kg

Fr = m . a, 40N = m . 100m/s², m = 40/100 , m = 4 x 10/ 10² = 4 x 10 x 10-² = 4 X 10-¹ = 0,4 Logo m = 0,4 kg

F= $m \times a$ , onde F = força resultante, m = massa do corpo e a = aceleração do corpo.

• F= $m \times a$

• 40 = $m \times 100$

• m = $\frac{40}{100}$

• m = 0.4 kg

Newton's Second Law ---> F=ma ---> 40=100m ---> m=0.4kg

F=ma,m=F/a, where F is the net force =40/100 =0.4 kg

The force is $40N$ while the acceleration is $100 \frac{m}{s^2}$ .

By Newton's Second Law, $F=ma$ , $m$ , which is the mass of the ball in $kg$ , is $\frac{F}{a}$ , which is $\frac{40N}{100 \frac{m}{s^2}}=\boxed{0.4kg}$ .

P=m/f , m=P/f=40/100=0.4

Using Law of Newton II, We know that:

$F = ma$ , $F$ is the force in newton , $m$ is the mass in kg , and the accelerate $a$ . So, We get the mass, $m$ from $m = \frac{F}{a} = \frac{40}{100} = \mbox{0.4}$ m/s2 .

It is well known that F=ma .

We are given F=40 N , and a=100 m/s^2 .

Plugging these in to the formula and solving yields:

$40$ N $=m\cdot100$ m/s^2

$\boxed{m=0.4}$ kg