Mass Percentage Problem 1

Chemistry Level 2

At 0 ∘ C 0^\circ \text{C} , the solubility of N a C l \ce{NaCl} is 35.7 g / 100 g 35.7\text{ g}/100\text{ g} water. Calculate the mass percentage of saturated N a C l \ce{NaCl} solution at 0 ∘ C 0^\circ \text{C} .

You may refer to Chemistry - Mass Percentage note.
0% 26.31% 35.7% 64.3%

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Christopher Boo by Christopher Boo , 24, Singapore

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1 solution

Anish Puthuraya
Jan 26, 2014

Let's take 100 g 100g of water.
Hence,
to make a saturated solution of N a C l NaCl , we have to add 35.7 g 35.7g of N a C l NaCl into the water.

Now,
Mass Percentage = m s o l u t e m s o l u t i o n × 100 = \frac{m_{solute}}{m_{solution}} \times 100
Thus,
Mass Percentage = m N a C l m N a C l + m w a t e r × 100 = \frac{m_{NaCl}}{m_{NaCl}+m_{water}} \times 100

= 35.7 100 + 35.7 × 100 = \frac{35.7}{100+35.7} \times 100

= 26.31 = \boxed{26.31} %

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