Massive Particle de Broglie Wavelength

Compute the de Broglie wavelength of a massive particle with mass 1 g 1 \text{ g} traveling at 1 m / s 1 \text{ m}/\text{s} .

6.63 × 1 0 28 m 6.63 \times 10^{-28} \text{ m} 6.63 × 1 0 13 m 6.63 \times 10^{-13} \text{ m} 6.63 × 1 0 34 m 6.63 \times 10^{-34} \text{ m} 6.63 × 1 0 31 m 6.63 \times 10^{-31} \text{ m}

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1 solution

The formula for the de Broglie wavelength is h p \frac {h}{p} , where "h" is Planck's constant ( 6.626 1 0 34 m 2 k g s 6.626 \cdot 10^{-34} m^2 \frac {kg}{s} ) and "p" is the momentum of the particle ( m a s s × v e l o c i t y mass \times velocity ). Since momentum is in units of k g m s kg \cdot \frac {m}{s} we must first convert from grams to kilograms (1g 0.001 k g \rightarrow 0.001 kg ). Finally, we can input the values into the equation, yielding 6.626 1 0 34 m 2 k g s 0.001 k g 1 m s \frac {6.626 \cdot 10^{-34} m^2 \frac {kg}{s}}{0.001 kg \cdot 1 \frac {m}{s}} = 6.63 1 0 31 6.63 \cdot 10^{-31} m.

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Mattheos Hailemariam - 6 months, 1 week ago

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