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4 solutions
5.41 is not 5x41
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in latex form, we can write---\times or \cdot instead of multiplication.this is the dot form.
again, 5 ⋅ 4 1 and 5 . 4 1 is not same...............:D
1 0 3 2 − 1 0 2 2 − 4 × 5 1 = ( 1 0 3 + 1 0 2 ) ( 1 0 3 − 1 0 2 ) − 2 0 5 = 2 0 5 − 2 0 5 = 0
1 0 3 2 − 1 0 2 2 − 5 ⋅ 4 1 = ( 1 0 2 + 1 ) 2 − 1 0 2 2 − 5 ⋅ 4 1 = 1 0 2 2 + 2 ( 1 0 2 ) + 1 − 1 0 2 2 − 5 ⋅ 4 1 = 2 0 5 − 2 0 5 = 0
⇒ ( 1 0 3 2 − 1 0 2 2 ) − 5 × 4 1
= 2 0 5 − 5 × ( 4 0 + 1 )
= 2 0 5 − 2 0 0 − 5
= 0
the answer is 0