Math always use to solve problems
Classical Mechanics
Level
pending
if a particle position define as this equation P=A cos(wt) + B sin(wt) where A,B,w is const number what is the correct answer of the squaring the velocity (v^2)?
v^2=A^2(w^2+B^2-P^2)
v^2=w^2(A^2+B^2-P^2)
v^2=A^2(w^2-B^2+P^2)
v^2=w^2(A^2-B^2+P^2)
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