Math Counts 6

Algebra Level 2

The Fibonacci sequence is defined by the function F(n) = F(n-2) + F(n-1), for n>2 and F(1)=F(2)=1. What is the value of F(11)?


The answer is 89.

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1 solution

Henry U
Oct 31, 2018

Using the given definition we get the following values

F ( 1 ) = 1 F(1) = 1

F ( 2 ) = 1 F(2) = 1

F ( 3 ) = F ( 2 ) + F ( 1 ) = 2 F(3) = F(2) + F(1) = 2

F ( 4 ) = F ( 3 ) + F ( 2 ) = 3 F(4) = F(3) + F(2) = 3

F ( 5 ) = F ( 4 ) + F ( 3 ) = 5 F(5) = F(4) + F(3) = 5

. . . ...

F ( 9 ) = F ( 8 ) + F ( 7 ) = 34 F(9) = F(8) + F(7) = 34

F ( 10 ) = F ( 9 ) + F ( 8 ) = 55 F(10) = F(9) + F(8) = 55

F ( 11 ) = F ( 10 ) + F ( 9 ) = 89 F(11) = F(10) + F(9) = \boxed{89}

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