It's a product? Not a sum?

Calculus Level 4

lim n r = 3 n r 3 2 3 r 3 + 2 3 \large \displaystyle \lim_{n \to \infty} \prod_{r=3}^{n} \dfrac{r^3 - 2^3}{r^3 + 2^3}

If the above limit can be expressed in the form a b \dfrac{a}{b} where a a and b b are coprime positive integers, find the value of a + b a+b .


The answer is 9.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

First Last
Apr 18, 2017

r = 3 n r 3 8 r 3 + 8 = r = 3 n ( r 2 ) ( r 2 + 2 r + 4 ) ( r + 2 ) ( r 2 2 r + 4 ) \displaystyle\prod_{r=3}^n\frac{r^3-8}{r^3+8} = \prod_{r=3}^n\frac{(r-2)(r^2+2r+4)}{(r+2)(r^2-2r+4)} As n approaches infinity, the terms in each product cancel out leaving:

1 5 × 2 6 × 3 7 × 4 8 × 5 9 × 6 10 × . . . × 19 7 × 28 12 × 39 19 × 52 28 × . . . = 2 7 \displaystyle\frac{1}{5}\times\frac{2}{6}\times\frac{3}{7}\times\frac{4}{8}\times\frac{5}{9}\times\frac{6}{10}\times...\quad\times\frac{19}{7}\times\frac{28}{12}\times\frac{39}{19}\times\frac{52}{28}\times... = \boxed{\frac{2}{7}}

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...