One pipe can fill a pool 1.25 times faster than a second pipe. When both pipes are opened, they fill the pool in five hours. How long would it take to fill the pool if only the slower pipe is used?
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Convert to rates: hours to complete job: fast pipe: f slow pipe: 1.25f together: 5
completed per hour: fast pipe: 1/f slow pipe: 1/1.25f together: 1/5
adding their labor:
1/f + 1/1.25f = 1/5
multiplying through by 5f:
5 + 5/1.25 = f 5 + 4 = f = 9
Then 1.25f = 11.25, so the slower pipe takes 11.25 hours.