If a prism has edges, how many vertices does it have?
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[A prism is a polyhedron comprising an n-sided polygonal base, a second base which is a translated copy of the first, and n other faces joining corresponding sides of the two bases. All cross-sections parallel to the bases are translations of the bases.]
The vertices of a prism are divided into 2 equal parts for 2 polygons. So each of the polygon has v / 2 ( v = number of vertices) edges. Then the vertices of polygons are connected one to one. From this we get v / 2 edges (equal to the number of vertices of each polygon).
So total number of edges = v / 2 + v / 2 + v / 2 = 3 ∗ v / 2 = e ( e = number of edges)
Now, 3 ∗ v / 2 = e
= > v = 2 ∗ e / 3 = 2 ∗ 3 4 2 / 3 = 2 2 8