Mathematical constant together

Calculus Level pending

If the limit lim j lim n i = 1 k = 1 n l = 1 k sin 1 ( π n 2020 n + ( j + 1 ) l ) tan 1 ( π Γ ( 1 n 2020 ) n + ( i + 1 ) ( k l + 1 ) ) ( i + 1 ) 1 ln ( 2 + j ) 1 + j j ln ( i + 1 ) 1 + j ln ( i + 2 ) \lim_{j\to\infty}\lim_{n\to\infty}\sum_{i=1}^{\infty}\sum_{k=1}^n\sum_{l=1}^{k}\sin^{-1} \left(\frac{\pi^{n^{2020}}}{n+(j+1)l}\right)\tan^{-1}\left(\frac{\pi^{-\Gamma\left(\frac{1}{n^{2020}}\right)}}{n+(i+1)(k-l+1)}\right)\frac{(i+1)^{-1}}{\ln(2+j)^{\sqrt[j]{1+j}}}\frac{\ln(i+1)^{1+j}}{\ln(i+2)} = π γ e ( ln ( A a b π ) c ) ζ ( b ) =\frac{\pi^{\gamma}}{e}\left(\ln \left(\frac{A^{a}}{b\pi}\right)-c \right)\zeta(b) where a , b , c a,b,c are real numbers such that b b is a prime.Find the value of π c ( a + b ) \pi c(a+b) .


Notation: γ , A , e , Γ \gamma, A,e , \Gamma are Euler-Mascheroni Glashier-kinkelin constants, Euler's number and Gamma function respectively.


This is an original problem and inspired by limit of sine sum and proposed problem to Romanian mathematical Magazine where closed form was supposed to be proved .


The answer is 25.38727.

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