Professor Ávila gave Esmeralda an equation of the form , where and are real numbers. Esmeralda, by accident, solved the equation and got a solution that is equal to the correct one minus 60. If the correct solution is of the form , where and are integers, what is the value of ?
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a x = b ⇒ x = a b = R ; b x = a ⇒ x = b a = r ; b a = a b 1 ⇒ r = R 1 . As r = ( R − 6 0 ) , ( R − 6 0 ) = R 1 ⇒ R 2 − 6 0 R − 1 = 0 ⇒ R = 2 6 0 + 3 6 0 4 ⇒ R = 2 6 0 + 2 9 0 1 ⇒ m + n = 3 0 + 9 0 1 ⇒ m = 3 0 and n = 9 0 1 ⇒ m + n = 9 3 1
Note : as the correct solution (R) is of the form m + n , I only represented the solution R = 2 6 0 + 3 6 0 4 , because the solution R = 2 6 0 − 3 6 0 4 is not the correct one.