Matrices and Determinants!

Algebra Level 5

S = k = 1 7 det ( A + ω k 1 B ) + k = 1 7 det ( B + ω k 1 A ) det ( A ) + det ( B ) \large{S= \dfrac{\displaystyle \sum_{k=1}^{7} \det(A + \omega^{k-1}B) + \sum_{k=1}^{7} \det(B + \omega^{k-1}A) }{\det(A) + \det(B)} }

Let A , B M 7 ( C ) A,B \in M_{7} (\mathbb C) where M 7 ( C ) M_{7} (\mathbb C) denotes a square matrix of order 7 × 7 7 \times 7 having complex entities in it. Let ω = e 2 π i / 7 \large{\omega = e^{2\pi i / 7}} . Then find the value of S S upto three correct places of decimals.


The answer is 14.000.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Mark Hennings
Jun 26, 2018

Note that f ( t ) = A + t B f(t) = \big|A + tB\big| is a polynomial of degree 7 7 in t t , so that f ( t ) = j = 0 7 c j t j f(t) \; = \; \sum_{j=0}^7 c_jt^j where c 0 = f ( 0 ) = A c_0 = f(0) = |A| and c 7 = B c_7 = |B| . Then k = 1 7 f ( ω k 1 ) = j = 0 7 c j k = 1 7 ω j ( k 1 ) = 7 ( c 0 + c 7 ) = 7 ( A + B ) \sum_{k=1}^7 f(\omega^{k-1}) \; = \; \sum_{j=0}^7 c_j\sum_{k=1}^7 \omega^{j(k-1)} \; = \; 7(c_0 + c_7) \; = \; 7(|A|+|B|) since ω j \omega^{j} is a primitive 7 7 th root of unity, so that k = 1 7 ω j ( k 1 ) = 0 \sum_{k=1}^7 \omega^{j(k-1)} = 0 , for all 1 j 6 1 \le j \le 6 .

Similarly k = 1 7 g ( ω k 1 ) = 7 ( A + B ) \sum_{k=1}^7 g(\omega^{k-1}) \; = \; 7(|A| + |B|) where g ( t ) = A t + B g(t) = \big|At + B\big| , which makes the answer 7 + 7 = 14 7 + 7 = \boxed{14} . Of course we must assume that A + B 0 |A|+|B| \neq 0 .

Could you please explain c7=|B|.

Jagannath Behera - 2 years, 11 months ago

Log in to reply

t 7 f ( t 1 ) = g ( t ) t^7f(t^{-1})=g(t) , from which we have c 7 = g ( 0 ) = B c_7=g(0)=|B| .

Mark Hennings - 2 years, 11 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...