Max height !!!
Calculus
Level
2
A body is thrown from earth's surface vertically upwards with velocity 'v', which varies with time as v=(29.4-9.8t) m/s. Find the maximum height reached by the body.
The answer is 44.1.
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1 solution
V=24.4-9.8t Integrate to obtain distance equation s = 29.4t - 4.9t^2 since it is thrown upward, the change in direction (up to down) means V=0 substitute 0 to velocity formula to get t t=3 at 3 seconds, the object changed direction substitute 3 to distance formula s = 44.1