A cubical block of wood of edge 3cm floats in water. The lower surface of the cube just touches the the free-end spring fixed at the bottom of a pot. Find the max weight that can be put on the block without wetting it. Density of wood=800kg/m^(3). Spring constant of spring=50N/m. Answer in Newton(N).
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let mass of block=m,mass of thing put on it=M
when the block just touches the spring,
Mg=Fup
(27/1000000)(800)=(1000)(volume immersed)
(27/1000000)(8)(1/10)=(9/10000)(y/100) ((y=edge of volume immersed in water))
2.4=y
0.6=x ((x=edge of volume above water))
now, when something is put on the block
(m+M)g=Fup+kx
(27/1250 + M)(10)=(1000)(27/1000000)(10)+(50)(6/1000)
After solving we get,
Mg=0.354N